Question:
The number of ways of giving 20 distinct oranges to 3 children such that each child gets at least one orange is______
The number of ways of giving 20 distinct oranges to 3 children such that each child gets at least one orange is______
Updated On: Mar 25, 2026
Show Solution
Verified By Collegedunia
Correct Answer: 348
Solution and Explanation
Total Cases:
\[ 3^{20} \]
Subtracting Invalid Cases:
- Case 1: One child receives no orange: \[ \binom{3}{1} \cdot 2^{20 - 2} \]
- Case 2: Two children receive no orange: \[ \binom{3}{2} \cdot 1^{20} \]
Final Calculation:
\[ \text{Total} - (\text{One child receives no orange} + \text{Two children receive no orange}) \]
\[ = 3^{20} - \binom{3}{1} \cdot 2^{20 - 2} + \binom{3}{2} \cdot 1^{20} \]
\[ = 3483638676 \]
Was this answer helpful?
0
0
Top JEE Main Mathematics Questions
- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
- If , then the general value of is:
- The general solution of
- If the constant term in the binomial expansion of $\left(\frac{x^{\frac{3}{2}}}{2}-\frac{4}{x^l}\right)^9$ is $-84$ and the coefficient of $x^{-3 l}$ is $2^\alpha \beta$, where $\beta<0$ is an odd number, then $|\alpha l-\beta|$ is equal to_____
View More Questions
Top JEE Main permutations and combinations Questions
- Five people are distributed in four identical rooms. A room can also contain zero people. Find the number of ways to distribute them.
- The number of ways to distribute the 21 identical apples to three children’s so that each child gets at least 2 apples.
- Let \( \alpha = \frac{(4!)!}{(4!)^{3!}} \) and \( \beta = \frac{(5!)!}{(5!)^{4!}} \). Then:
- Number of ways of arranging 8 identical books into 4 identical shelves where any number of shelves may remain empty is equal to
- In an examination of Mathematics paper, there are 20 questions of equal marks and the question paper is divided into three sections : A, B and C . A student is required to attempt total 15 questions taking at least 4 questions from each section. If section A has 8 questions, section B has 6 questions and section C has 6 questions, then the total number of ways a student can select 15 questions is _______ .
View More Questions
Top JEE Main Questions
- In a hydrogen like atom, when an electron jumps from the $M$ - shell to the $L$ - shell, the wavelength of emitted radiation is $\lambda$. If an electron jumps from $N$-shell to the $L$-shell, the wavelength of emitted radiation will be :
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
View More Questions