
The molecular weight of \( C_8H_8O_2 \) is calculated as:
Molecular weight = \( 12 \times 8 + 1 \times 8 + 16 \times 2 = 96 + 8 + 32 = 136 \)
Next, we calculate the moles of product \( D \) formed:
Moles of product \( D \) = \( \frac{15}{3} \times 0.8 \times 0.5 = \frac{3}{3} = 1 \)
Therefore, the weight of product \( D \) is:
Weight of product \( D \) = \( 1 \times 136 = 136 \, \text{g} \)


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