The wave number of the first emission line in the Balmer series of H-Spectrum is : (\(R\) = Rydberg constant)
Show Hint
- \(\frac{5}{36}R\)
- \(\frac{9}{400}R\)
- \(\frac{7}{6}R\)
- \(\frac{3}{4}R\)
The Correct Option is A
Solution and Explanation
Balmer series: \(n_1 = 2\); first line: \(n_2 = 3\).
\(\bar{\nu} = R\left(\frac{1}{4} - \frac{1}{9}\right) = R\cdot\frac{9-4}{36} = \frac{5}{36}R\).
Answer: (1) \(\frac{5}{36}R\)
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