The given question asks about the van't Hoff factor (\(i\)) for a solution of acetic acid (CH₃COOH) in water. Let's understand the concept of the van't Hoff factor and its application to CH₃COOH:
Van't Hoff Factor Explanation:
- The van't Hoff factor, \(i\), is a measure of the extent of dissociation or association of solute particles in a solution.
- For a solute that dissociates completely into \(n\) particles, \(i = n\). For a solute that does not dissociate (or associate), \(i = 1\).
- If the solute partially dissociates, \(i\) will have a value between 1 and \(n\).
Dissociation of CH₃COOH:
- Acetic acid (CH₃COOH) is a weak acid and partially dissociates in water.
- The dissociation can be represented as: \(\text{CH}_3\text{COOH} \rightleftharpoons \text{CH}_3\text{COO}^- + \text{H}^+\).
- Assuming partial dissociation, some molecules of CH₃COOH remain undissociated, leading to a van't Hoff factor \(i\) between 1 (no dissociation) and 2 (complete dissociation).
Conclusion:
Since CH₃COOH only partially dissociates in water, the van't Hoff factor for a CH₃COOH solution in water will be between 1 and 2.
Therefore, the correct answer is: Between 1 and 2.