Question:
The value of \(\log_6 2 + \log_6 3\) is:
The value of \(\log_6 2 + \log_6 3\) is:
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Remember that \(\log_b b = 1\) and use the product rule \(\log_b x + \log_b y = \log_b (x \times y)\) to simplify logarithmic expressions.
Updated On: May 13, 2025
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The Correct Option is B
Solution and Explanation
Using the logarithmic property \(\log_b x + \log_b y = \log_b (x \times y)\), we get:
\[
\log_6 2 + \log_6 3 = \log_6 (2 \times 3) = \log_6 6
\]
Since \(\log_b b = 1\), we have:
\[
\log_6 6 = 1
\]
Thus, the correct answer is 1.
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