Question:
The turbidity of raw water entering a sedimentation tank is \(120\) NTU. After sedimentation, the turbidity is reduced to \(30\) NTU. What is the turbidity removal efficiency of the sedimentation process?
The turbidity of raw water entering a sedimentation tank is \(120\) NTU. After sedimentation, the turbidity is reduced to \(30\) NTU. What is the turbidity removal efficiency of the sedimentation process?
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Removal efficiency:
\[
\boxed{
\eta=
\frac{C_i-C_f}{C_i}\times100
}
\]
where \(C_i\) = initial value and \(C_f\) = final value.
Updated On: Jul 23, 2026
- \(50\%\)
- \(90\%\)
- \(80\%\)
- \(75\%\)
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The Correct Option is D
Solution and Explanation
Removal efficiency is given by
\[
\text{Efficiency}=
\frac{\text{Initial Turbidity}-\text{Final Turbidity}}
{\text{Initial Turbidity}}
\times100
\]
Substituting the given values,
\[
=
\frac{120-30}{120}\times100
=
\frac{90}{120}\times100
=75\%
\]
Hence,
\[
\boxed{75\%}
\]
Therefore,
\[
\boxed{(D)}
\]
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