Question:

The total number of natural numbers that lie between 10 and 300 and are divisible by 9 is

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Count multiples of 9 up to 300, subtract those up to 10: floor(300/9) - floor(10/9) = 33 - 1 = 32.
Updated On: Jul 15, 2026
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The Correct Option is A

Solution and Explanation

Step 1: Find the first and last terms.
The first natural number greater than 10 that is divisible by 9 is 18. The last one less than 300 is 297 (since \(300/9=33.33\), so \(9\times33=297\)).

Step 2: Set up the arithmetic progression.
This forms an AP with first term 18, last term 297, and common difference 9.

Step 3: Solve for the number of terms.
\(297=18+(n-1)\times9 \Rightarrow 279=(n-1)\times9 \Rightarrow n-1=31 \Rightarrow n=32\).

Step 4: Final Answer.
There are 32 such numbers, so option A is correct.
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