Question

The Throw of a fault is 4 m and the Heave is 3 m. The Dip separation of the fault, in meters, is ............... (In integer)

Hint:

The dip separation can be calculated using the Pythagorean theorem, considering Throw and Heave as the sides of a right triangle.

Answer 1

Step 1: Understanding the formula.
For a fault, the dip separation \( S \) can be calculated as: \[ S = \sqrt{\text{Throw}^2 + \text{Heave}^2} \] Step 2: Substitute the given values.
Throw = 4 m, Heave = 3 m. Therefore: \[ S = \sqrt{(4)^2 + (3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5 \] Final Answer: \[ \boxed{5} \]