Step 1: Relationship Between Surface Area and Mass Number
The surface area of a nucleus is proportional to the square of its radius:
\[
A \propto R^2
\]
Since nuclear radius is related to mass number:
\[
R \propto A^{1/3}
\]
Step 2: Compute the Mass Number Ratio
\[
\frac{R_1}{R_2} = \sqrt{\frac{9}{25}} = \frac{3}{5}
\]
\[
\left(\frac{M_1}{M_2}\right)^{1/3} = \frac{3}{5}
\]
Cubing both sides:
\[
\frac{M_1}{M_2} = \left(\frac{3}{5}\right)^3 = \frac{27}{125}
\]
Thus, the correct answer is \( 27:125 \).
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Approach Solution -2
Given:
- The surface areas of two nuclei are in the ratio \( 9 : 25 \).
We need to find the ratio of their mass numbers.
Step 1: Relation between surface area and radius of a nucleus:
The surface area \( S \) of a spherical nucleus is:
\[
S = 4 \pi r^2
\]
where \( r \) is the radius of the nucleus.
Step 2: Using the ratio of surface areas:
\[
\frac{S_1}{S_2} = \frac{9}{25} = \frac{r_1^2}{r_2^2}
\]
Taking square root on both sides:
\[
\frac{r_1}{r_2} = \sqrt{\frac{9}{25}} = \frac{3}{5}
\]
Step 3: Relation between radius and mass number \( A \):
The radius of a nucleus is related to its mass number by:
\[
r = r_0 A^{1/3}
\]
where \( r_0 \) is a constant.
Step 4: Using the ratio of radii:
\[
\frac{r_1}{r_2} = \left( \frac{A_1}{A_2} \right)^{1/3} = \frac{3}{5}
\]
Cubing both sides:
\[
\frac{A_1}{A_2} = \left( \frac{3}{5} \right)^3 = \frac{27}{125}
\]
Therefore, the ratio of the mass numbers of the two nuclei is:
\[
\boxed{27 : 125}
\]