Step 1: Recall the formula for the sum of zeroes.
For a quadratic polynomial \(ax^2 + bx + c\), the sum of its zeroes is given by:
\[
\text{Sum of zeroes} = -\frac{b}{a}
\]
Step 2: Substitute the values.
Here, \(a = 3\), \(b = 5\), and \(c = 2\).
So,
\[
\text{Sum of zeroes} = -\frac{b}{a} = -\frac{5}{3}
\]
Step 3: Conclusion.
Hence, the sum of zeroes of the polynomial \(3x^2 + 5x + 2\) is \(-\dfrac{5}{3}\).