Question:

The sum of two numbers is 528 and their HCF is 33. The number of pairs of such numbers that can be formed is

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For HCF problems, divide the numbers by the HCF first. Then count coprime pairs satisfying the reduced sum.
Updated On: Jul 15, 2026
  • \(8\)
  • \(6\)
  • \(5\)
  • \(4\)
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The Correct Option is D

Solution and Explanation

Concept: If HCF of two numbers is \(33\), let the numbers be: \[ 33x \text{ and } 33y \] where: \[ HCF(x,y)=1 \]

Step 1:
Use the sum condition.
Given: \[ 33x+33y=528 \] \[ 33(x+y)=528 \] \[ x+y=16 \]

Step 2:
Find coprime pairs whose sum is 16.
Possible pairs: \[ (1,15) \] \[ (3,13) \] \[ (5,11) \] \[ (7,9) \] Check HCF: \[ HCF(1,15)=1 \] \[ HCF(3,13)=1 \] \[ HCF(5,11)=1 \] \[ HCF(7,9)=1 \] All valid.

Step 3:
Count the pairs.
Total pairs: \[ 4 \] Thus, the required answer is: \[ \boxed{4} \]
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