The standard electrode potentials \(\left(E^{\circ}_{M^+/M}\right)\) of four metals A, B, C and D are \(-1.2\ \mathrm{V}\), \(0.6\ \mathrm{V}\), \(0.85\ \mathrm{V}\) and \(-0.76\ \mathrm{V}\), respectively. The sequence of deposition of metals on applying potential is
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- \(\mathrm{B}\gt\mathrm{D}\gt\mathrm{C}\gt\mathrm{A}\)
- \(\mathrm{A}\gt\mathrm{C}\gt\mathrm{B}\gt\mathrm{D}\)
- \(\mathrm{C}\gt\mathrm{B}\gt\mathrm{D}\gt\mathrm{A}\)
- \(\mathrm{D}\gt\mathrm{A}\gt\mathrm{B}\gt\mathrm{C}\)
The Correct Option is C
Solution and Explanation
Order of \(E^{\circ}\): C (0.85) \(\gt\) B (0.6) \(\gt\) D (-0.76) \(\gt\) A (-1.2)
Answer: (3) C > B > D > A
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