Step 1: Understanding the Question:
The question asks to find the height of a water column that would exert the same pressure as a given height of a mercury column.
Step 2: Key Formula or Approach:
The pressure ($P$) exerted by a column of liquid is given by $P = \rho g h$. Since the pressure is the same for both columns, we can write:
\[ P = \rho_{mercury} g h_{mercury} = \rho_{water} g h_{water} \]
The specific gravity (SG) of a substance is the ratio of its density to the density of water: $SG_{mercury} = \rho_{mercury} / \rho_{water}$.
So, $\rho_{mercury} = SG_{mercury} \times \rho_{water}$.
Substituting this into the pressure equation and canceling $g$ and $\rho_{water}$ gives the relationship:
\[ h_{water} = SG_{mercury} \times h_{mercury} \]
Step 3: Detailed Explanation:
We are given:
- Specific gravity of mercury ($SG_{mercury}$) = 13.6
- Height of mercury column ($h_{mercury}$) = 20 cm
Now, calculate the equivalent height of the water column:
\[ h_{water} = 13.6 \times 20 \text{ cm} \]
\[ h_{water} = 272 \text{ cm} \]
This is also equal to 2.72 m. Comparing with the options, 272 cm is available.
Step 4: Final Answer:
The equivalent height of the water column is 272 cm.