Question

The relative density of silver is 10.8. If the density of water is 1000 kg/m\(^3\), then the density of silver will be-

• A. \(10.8\times10^{-3}\) kg/m\(^3\)
• B. \(10.8\times10^{3}\) kg/m\(^3\)
• C. 10.8 kg/m\(^3\)
• D. \(1.08\times10^{-3}\) kg/m\(^3\)

Hint:

Relative density is a ratio and therefore has no unit.

Answer 1

The Correct Option is B

Concept: Relative density is defined as \[ \text{Relative Density} = \frac{\text{Density of Substance}} {\text{Density of Water}} \] Therefore, \[ \text{Density of Substance} = \text{Relative Density} \times \text{Density of Water} \]

Step 1: Write the given values.
\[ \text{Relative Density of Silver}=10.8 \] \[ \text{Density of Water}=1000\text{ kg/m}^3 \]

Step 2: Calculate the density of silver.
\[ \text{Density of Silver} = 10.8\times1000 \] \[ =10800\text{ kg/m}^3 \] \[ =10.8\times10^3\text{ kg/m}^3 \] \(10.8\times10^3\text{ kg/m}^3\)