The relationship between the magnetic susceptibility $ \chi $ and the magnetic permeability $ \mu $ is given by:
$ \mu_0 $ is the permeability of free space and $ \mu_r $ is relative permeability.
The problem asks for the correct relationship between magnetic susceptibility (\(\chi\)) and magnetic permeability (\(\mu\)), also involving the permeability of free space (\(\mu_0\)) and relative permeability (\(\mu_r\)).
The solution is derived from the fundamental definitions of magnetic quantities.
Step 1: Start with the fundamental relationship between \( \vec{B} \), \( \vec{H} \), and \( \vec{M} \).
\[ \vec{B} = \mu_0 (\vec{H} + \vec{M}) \]
Step 2: Substitute the definition of magnetic susceptibility (\( \vec{M} = \chi \vec{H} \)) into the equation from Step 1.
\[ \vec{B} = \mu_0 (\vec{H} + \chi \vec{H}) \]
Step 3: Factor out the magnetic field strength \( \vec{H} \) from the expression.
\[ \vec{B} = \mu_0 (1 + \chi) \vec{H} \]
Step 4: Use the definition of magnetic permeability (\( \vec{B} = \mu \vec{H} \)) to relate \( \mu \) and \( \chi \).
By comparing the equation from Step 3 with \( \vec{B} = \mu \vec{H} \), we can equate the expressions for \( \vec{B} \):
\[ \mu \vec{H} = \mu_0 (1 + \chi) \vec{H} \]
Canceling \( \vec{H} \) from both sides, we get the relationship between \( \mu \), \( \mu_0 \), and \( \chi \):
\[ \mu = \mu_0 (1 + \chi) \]
Step 5: Rearrange the equation to express \( \chi \) in terms of \( \mu \) and \( \mu_0 \).
Divide both sides of the equation by \( \mu_0 \):
\[ \frac{\mu}{\mu_0} = 1 + \chi \]
Now, solve for \( \chi \):
\[ \chi = \frac{\mu}{\mu_0} - 1 \]
We can also express this using the definition of relative permeability, \( \mu_r = \frac{\mu}{\mu_0} \):
\[ \chi = \mu_r - 1 \]
Comparing our derived result with the given options, the correct relationship is:
\( \chi = \frac{\mu}{\mu_0} - 1 \)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)