Step 1: Check reflexive property
A relation is reflexive if:
\[
(a,a)\in R
\quad \forall a\in\mathbb R
\]
Given:
\[
a\leq a^2
\]
Consider:
\[
a=\frac12
\]
Then:
\[
\frac12 \nleq \frac14
\]
which is false.
Hence relation is:
\[
\text{not reflexive}
\]
Thus:
\[
(A)\ \text{is false}
\]
Step 2: Check symmetric property
A relation is symmetric if:
\[
(a,b)\in R
\Rightarrow
(b,a)\in R
\]
Take:
\[
a=1,\quad b=2
\]
Then:
\[
1\leq2^2
\]
so:
\[
(1,2)\in R
\]
Now check:
\[
2\leq1^2
\]
which is false.
Hence relation is:
\[
\text{not symmetric}
\]
Thus:
\[
(B)\ \text{is true}
\]
Step 3: Check transitive property
A relation is transitive if:
\[
(a,b)\in R
\text{ and }
(b,c)\in R
\Rightarrow
(a,c)\in R
\]
Take:
\[
a=4,\quad b=3,\quad c=2
\]
Then:
\[
4\leq3^2=9
\]
and:
\[
3\leq2^2=4
\]
So:
\[
(a,b)\in R,\quad (b,c)\in R
\]
But:
\[
4\leq2^2=4
\]
This is true, so choose another example.
Take:
\[
a=10,\quad b=4,\quad c=2
\]
Then:
\[
10\leq4^2=16
\]
and:
\[
4\leq2^2=4
\]
But:
\[
10\leq2^2=4
\]
which is false.
Hence relation is:
\[
\text{not transitive}
\]
Thus:
\[
(D)\ \text{is false}
\]
Therefore relation is:
\[
\text{not symmetric and neither reflexive nor transitive}
\]
Hence correct statements are:
\[
(B)\ \text{and}\ (C)
\]
Therefore:
\[
\boxed{\text{(C)}}
\]