To find the angle of a prism when the refractive index of its material is given, and the angle of minimum deviation is equal to the angle of the prism, we utilize the formula for the angle of deviation in a prism.
The formula relating the refractive index (\( n \)), the angle of the prism (\( A \)), and the angle of minimum deviation (\( \delta_m \)) is given by:
\(n = \frac{\sin\left(\frac{A + \delta_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}\)
Given:
Substitute \( \delta_m = A \) in the formula:
\(n = \frac{\sin(A)}{\sin\left(\frac{A}{2}\right)}\)
Given \( n = 3 \), the equation becomes:
\(3 = \frac{\sin(A)}{\sin\left(\frac{A}{2}\right)}\)
We need to find the angle \( A \) such that the above equation holds.
By solving this equation using trigonometric identities and known values, we find:
\(A = 60^\circ\)
This solution matches with the provided options, confirming that the angle of the prism is indeed 60°.
Therefore, the correct answer is 60°.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

Refer the figure below. \( \mu_1 \) and \( \mu_2 \) are refractive indices of air and lens material respectively. The height of image will be _____ cm.

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)