Question:

The ratio of Undergraduate and post graduate pursuing students from state B to Undergraduate and post graduate pursuing students from state A is ?

Show Hint

To perform fast division, estimate using round figures:
\[ \text{Ratio} \approx \frac{57000}{34500} \approx \frac{57}{34.5} \approx 1.65 \]
This approach helps you choose the correct option quickly without long division.
  • 1.87
  • 1.16
  • 1.25
  • 1.65
Show Solution
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
To find the ratio of combined categories across two datasets, we first calculate the total sum of the specified categories in both states and then divide them.
Key Formula or Approach:
- Combined Value = \((\text{Percentage}_1 + \text{Percentage}_2) \times \text{Total Population}\)
- Ratio = \(\frac{\text{Combined Value}_B}{\text{Combined Value}_A}\)

Step 2: Detailed Explanation:

Let us calculate the combined number of undergraduate and postgraduate students for both states:
- For State B:
- Percentage of Undergraduates = \(40\%\)
- Percentage of Postgraduates = \(26\%\)
- Total combined percentage = \(40\% + 26\% = 66\%\)
- Total population, \(N_B = 86500\)
\[ \text{Combined Value}_B = 86500 \times 0.66 = 57090 \]
- For State A:
- Percentage of Undergraduates = \(28\%\)
- Percentage of Postgraduates = \(34\%\)
- Total combined percentage = \(28\% + 34\% = 62\%\)
- Total population, \(N_A = 55750\)
\[ \text{Combined Value}_A = 55750 \times 0.62 = 34565 \]
- Calculating the Ratio:
\[ \text{Ratio} = \frac{57090}{34565} \approx 1.6516 \approx 1.65 \]

Step 3: Final Answer:

The ratio is approximately 1.65 (Option D).
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