Remember to simplify ratios carefully and square both sides when dealing with square root equations.
The power \( P \) of a motor is given by: \[ P = \frac{mgh}{t}, \] where \( m \) is the mass of water raised, \( g \) is the acceleration due to gravity, \( h \) is the height, and \( t \) is the time taken.
For the two motors: \[ P_1 = \frac{300 \cdot g \cdot 100}{5 \cdot 60}, \quad P_2 = \frac{50 \cdot g \cdot 100}{2 \cdot 60}. \]
Simplify the powers: \[ P_1 = \frac{300 \cdot 100}{5 \cdot 60}, \quad P_2 = \frac{50 \cdot 100}{2 \cdot 60}. \]
\[ P_1 = 100, \quad P_2 = \frac{250}{6}. \]
The ratio of powers is given by: \[ \frac{P_1}{P_2} = \frac{100}{\frac{250}{6}} = \frac{100 \cdot 6}{250} = \frac{600}{250} = \frac{12}{5}. \]
Equating this with the given ratio: \[ \frac{3\sqrt{x}}{\sqrt{x+1}} = \frac{12}{5}. \]
Cross-multiply: \[ 5 \cdot 3\sqrt{x} = 12 \cdot \sqrt{x+1}. \]
Simplify: \[ 15\sqrt{x} = 12\sqrt{x+1}. \]
Square both sides: \[ 225x = 144(x+1). \]
Expand and simplify: \[ 225x = 144x + 144. \]
\[ 225x - 144x = 144. \]
\[ 81x = 144 \quad \Rightarrow \quad x = \frac{144}{81} = 16. \]
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)