Step 1: Assume the incomes. Let the monthly incomes of A and B be \(7x\) and \(6x\) respectively.
Step 2: Assume the expenditures. Let the monthly expenditures of A and B be \(5y\) and \(4y\) respectively.
Step 3: Use the saving condition. Savings = Income – Expenditure.
- For A: \(7x - 5y = 600\)
- For B: \(6x - 4y = 600\)
Step 4: Form simultaneous equations. \[ 7x - 5y = 600 \quad ...(1) \] \[ 6x - 4y = 600 \quad ...(2) \]
Step 5: Simplify equations. From (2): \(6x - 4y = 600 \Rightarrow 3x - 2y = 300 \quad ...(3)\) Multiply (3) by 2: \[ 6x - 4y = 600 \] (Already the same form). Now solve (1): \[ 7x - 5y = 600 \] Multiply (3) by 5: \[ 15x - 10y = 1500 \] Multiply (1) by 2: \[ 14x - 10y = 1200 \] Subtract: \[ (15x - 10y) - (14x - 10y) = 1500 - 1200 \] \[ x = 300 \]
Step 6: Find incomes.
- Income of A = \(7x = 7 \times 300 = 2100\)
- Income of B = \(6x = 6 \times 300 = 1800\)
Step 7: Find sum. \[ \text{Total income} = 2100 + 1800 = 3900 \]
Step 8: Final Answer. \[ \text{Sum of incomes} = 2100 + 1800 = \boxed{3900} \]