The proposition \(\sim(p \vee \sim q) \vee \sim(p \vee q)\) is logically equivalent to:
Show Hint
- \(p\)
- \(q\)
- \(\sim p\)
- \(\sim q\)
The Correct Option is C
Solution and Explanation
The proposition becomes \((\sim p \wedge q) \vee (\sim p \wedge \sim q) = \sim p \wedge (q \vee \sim q) = \sim p \wedge T = \sim p\).
Answer: (3) \(\sim p\)
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