Equivalent statement to (p\(\to\)q) \(\vee\) (r\(\to\)q) will be
(p \(\wedge\) r) \(\to\) q
(p \(\vee\) r) \(\to\) q
(q \(\to\) r) \(\vee\) (p \(\vee\) r)
(r \(\to\) p) \(\wedge\) (q \(\to\) r)
| p | q | r | p → q | r → q | (p → q) \(\vee\) (r → q) | (p \(\wedge\) r) | (p \(\wedge\) r) → q |
| T | T | T | T | T | T | T | T |
| T | T | F | T | T | T | F | T |
| T | F | T | F | F | F | T | F |
| T | F | F | F | T | T | F | T |
| F | T | T | T | T | T | F | T |
| F | T | F | T | T | T | F | T |
| F | F | T | T | F | T | F | T |
| F | F | F | T | T | T | F | T |
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Mathematical reasoning or the principle of mathematical reasoning is a part of mathematics where we decide the truth values of the given statements. These reasoning statements are common in most competitive exams like JEE and the questions are extremely easy and fun to solve.
Mathematically, reasoning can be of two major types such as: