The proposition \(p \to \sim(p \wedge \sim q)\) is equivalent to :
Show Hint
- \((\sim p) \vee q\)
- \(q\)
- \((\sim p) \wedge q\)
- \((\sim p) \vee (\sim q)\)
The Correct Option is A
Solution and Explanation
By De Morgan: \(\sim(p \wedge \sim q) \equiv (\sim p) \vee q\).
So the proposition is \((\sim p) \vee (\sim p) \vee q \equiv (\sim p) \vee q\).
Answer: (1) \((\sim p) \vee q\)
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