The products of the following reactions \( X \) and \( Y \) respectively are Reaction:
The products of the following reactions \( X \) and \( Y \) respectively are Reaction:
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- LiAlH₄ reduces carboxyl (-COOH) to primary alcohol (-CH₂OH).
- SOCl₂ converts alcohols or carboxyl groups into acid chlorides (-COCl).
- H₂ with Pd-BaSO₄ (Lindlar's catalyst) selectively reduces acid chlorides to aldehydes (-CHO).
The Correct Option is A
Solution and Explanation
To determine the products \(X\) and \(Y\), we analyze the reaction sequence step by step:
-
Step 1: Formation of benzoyl chloride
Benzoic acid reacts with thionyl chloride:
\( C_6H_5COOH + SOCl_2 \rightarrow C_6H_5COCl + SO_2 + HCl \)
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Step 2: Formation of product X (Rosenmund reduction)
Benzoyl chloride is reduced using \( H_2 \) in presence of Pd/BaSO₄ to form benzaldehyde:
\( C_6H_5COCl + H_2 \rightarrow C_6H_5CHO + HCl \)
So, \( X = \text{benzaldehyde} \)
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Step 3: Formation of product Y (reduction)
Benzaldehyde is reduced using \( LiAlH_4 \) followed by hydrolysis:
\( C_6H_5CHO \xrightarrow[H_2O]{LiAlH_4} C_6H_5CH_2OH \)
So, \( Y = \text{benzyl alcohol} \)
Final Answer:
\( X = \text{benzaldehyde}, \quad Y = \text{benzyl alcohol} \)
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