Question:

The product formed upon heating methyl bromide with potassium tert-butoxide is ________.

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For Williamson synthesis: Best results with $1^\circ$ halide + $3^\circ$ alkoxide.
Updated On: Apr 17, 2026
  • Di-tert-butyl ether
  • Dimethyl ether
  • Isobutylene
  • tert-butyl methyl ether
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The Correct Option is D

Solution and Explanation

Step 1: Concept
This is a Williamson Ether Synthesis, which follows an $S_N2$ mechanism.
Step 2: Analysis
The reagents are a $1^\circ$ alkyl halide (methyl bromide) and a bulky alkoxide (potassium tert-butoxide).
Step 3: Mechanism
Bulky alkoxides favor elimination ($E2$) with hindered halides, but since the halide is methyl (least hindered), substitution ($S_N2$) occurs to form the ether.
Step 4: Conclusion
The product is tert-butyl methyl ether.
Final Answer:(D)
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