Question:
The probability that a non-leap year selected at random will have 53 Sundays or 53 Saturdays is:
The probability that a non-leap year selected at random will have 53 Sundays or 53 Saturdays is:
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For 365-day year:
\begin{itemize}
\item One extra day beyond 52 weeks.
\item Probability = favourable weekdays / 7.
\end{itemize}
Updated On: Mar 2, 2026
- \( \frac{1}{7} \)
- \( \frac{2}{7} \)
- \( 1 \)
- \( \frac{2}{365} \)
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The Correct Option is B
Solution and Explanation
Concept:
A non-leap year has 365 days = 52 weeks + 1 extra day.
So one weekday occurs 53 times.
Step 1: {\color{red}Possible extra days.}
The extra day can be any of 7 weekdays.
Step 2: {\color{red}Favourable cases.}
We want extra day = Sunday or Saturday.
Favourable outcomes = 2.
Step 3: {\color{red}Probability.}
\[
\frac{2}{7}
\]
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