Question

The probability that a non-leap year selected at random will have 53 Sundays or 53 Saturdays is:

• A. \( \frac{1}{7} \)
• B. \( \frac{2}{7} \)
• C. \( 1 \)
• D. \( \frac{2}{365} \)

Hint:

For 365-day year: \begin{itemize} \item One extra day beyond 52 weeks. \item Probability = favourable weekdays / 7. \end{itemize}

Answer 1

The Correct Option is B

Concept: A non-leap year has 365 days = 52 weeks + 1 extra day. So one weekday occurs 53 times. Step 1: {\color{red}Possible extra days.} The extra day can be any of 7 weekdays. Step 2: {\color{red}Favourable cases.} We want extra day = Sunday or Saturday. Favourable outcomes = 2. Step 3: {\color{red}Probability.} \[ \frac{2}{7} \]