Step 1: Set up the ages using a common multiplier.
Rahul : Father = 6 : 13, so let Rahul = \(6k\) and Father = \(13k\) for some positive number \(k\). Father : Sister = 13 : 5 uses the same father value \(13k\), so Sister = \(5k\). The mother's age is not fixed yet, only that Mother \(-\) Sister = 28 years, so Mother = \(5k+28\). We need Father \(-\) Mother = \(13k-(5k+28)=8k-28\), which depends only on \(k\).
Step 2: Check statement (1) alone.
Statement (1) says Rahul : Mother = 1 : 2, so Mother = \(2\times 6k = 12k\). Since we already found Mother = \(5k+28\), setting these equal gives \(12k = 5k+28\), so \(7k=28\) and \(k=4\). Then Father \(-\) Mother \(= 8(4)-28 = 32-28 = 4\) years. This is a single clean number, so statement (1) alone answers the question.
Step 3: Check statement (2) alone.
Statement (2) says Rahul and Sister differ by 4 years, that is \(6k - 5k = 4\) (Rahul being older since \(6k>5k\)), which gives \(k=4\) directly. Then Father \(-\) Mother \(= 8(4)-28=4\) years again. This also gives one clean number using statement (2) alone.
Step 4: Final answer.
Both statements, taken separately, let us solve for \(k\) and hence for Father \(-\) Mother, each giving 4 years.
\[ \boxed{\text{Either statement alone is sufficient}} \]