The possible number of 'triplet' codons from 6 different types of nucleotides in the DNA molecule is:
Show Hint
For 4 nucleotides: 4^3 = 64 codons.
- (6)^3
- (3)^6
- (6)^6
- (3)^3
The Correct Option is A
Solution and Explanation
This question tests knowledge of combinatorics and the genetic code.
Step 2: Key Formula or Approach:
The number of possible codons (triplets) from n types of nucleotides is n^3 (since each of the 3 positions can have n possibilities).
Step 3: Detailed Explanation:
If there are 6 different types of nucleotides, the number of possible triplet codons is:
\[ 6 \times 6 \times 6 = 6^3 = 216. \] Thus, the possible number of triplet codons from 6 nucleotides is (6)^3.
Other options:
- (3)^6 (B): Incorrect.
- (6)^6 (C): Incorrect.
- (3)^3 (D): Incorrect (would be for 3 nucleotides).
Thus, the correct answer is (6)^3.
Step 4: Final Answer:
Thus, the possible number of triplet codons is (6)^3, which corresponds to option (A).
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