Question:

The polymer obtained from the following reaction is :

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\(\mathrm{NaNO_2/H_3O^+}\) converts an aliphatic \(\mathrm{-NH_2}\) to \(\mathrm{-OH}\), giving a hydroxy acid that condenses to a polyester.
Updated On: Nov 5, 2026
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The Correct Option is D

Solution and Explanation

The starting material is 5-aminopentanoic acid, \(\mathrm{HOOC-(CH_2)_4-NH_2}\).
Step (i): \(\mathrm{NaNO_2/H_3O^+}\) (nitrous acid) diazotises the primary aliphatic amine, and the unstable aliphatic diazonium salt is replaced by water: \(\mathrm{-NH_2 \rightarrow -OH}\). Product: \(\mathrm{HOOC-(CH_2)_4-OH}\) (5-hydroxypentanoic acid).
Step (ii): polymerisation by condensation between \(\mathrm{COOH}\) of one molecule and \(\mathrm{OH}\) of the next gives a polyester with repeating unit \(\mathrm{-[O-(CH_2)_4-C(=O)]-}\).
Option (1) is a polyamide (amine retained), option (2) is nylon-6,6 type polyamide, options (3) and (4) are the polyester.
Answer: (4) \(\mathrm{-[O-(CH_2)_4-CO]_n-}\) (polyester)
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