Question:
The points of intersection of three lines $2X + 3Y - 5 = 0$, $5X - 7Y + 2 = 0$ and $9X - 5Y - 4 = 0$
The points of intersection of three lines $2X + 3Y - 5 = 0$, $5X - 7Y + 2 = 0$ and $9X - 5Y - 4 = 0$
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For line equations in $ax+by+c=0$ form, slope $m = -\frac{a}{b}$.
Updated On: Aug 6, 2025
- form a triangle
- are on lines perpendicular to each other
- are on lines parallel to each other
- are coincident
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The Correct Option is A
Solution and Explanation
Check if any two lines are parallel: Slopes are $-\frac{2}{3}$, $\frac{5}{7}$, and $\frac{9}{5}$ — all different, so all lines intersect pairwise at distinct points. This means the three lines form a triangle.
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