Question:
The pOH of 0.0005 M sulphuric acid is
The pOH of 0.0005 M sulphuric acid is
Updated On: Jun 21, 2022
- 5
- 3
- 11
- 12
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The Correct Option is C
Solution and Explanation
$ { H_2SO_4 <=> 2H^+ +SO_4^{2-}}$
So, $ {[H^+] = 2\times 0.0005 = 1 \times 10^{-3} \, M }$
$ {pH = - log [H^+] = - log(1\times 10^{-3}) }$
$ {pH = 3 }$
$\because {pH +pOH = 14 }$
???$ {3 +pOH = 14 }$
????????$ { pOH = 14 - 3 }$
????????$ {pOH = 14 }$
????????$ {pOH = 11 }$
So, $ {[H^+] = 2\times 0.0005 = 1 \times 10^{-3} \, M }$
$ {pH = - log [H^+] = - log(1\times 10^{-3}) }$
$ {pH = 3 }$
$\because {pH +pOH = 14 }$
???$ {3 +pOH = 14 }$
????????$ { pOH = 14 - 3 }$
????????$ {pOH = 14 }$
????????$ {pOH = 11 }$
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family