Question:
The oxidation state of Fe in the brown ring complex: \( [Fe(H_{2}O)_{5}NO]SO_{4} \) is
The oxidation state of Fe in the brown ring complex: \( [Fe(H_{2}O)_{5}NO]SO_{4} \) is
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Brown ring complex is an exception where Iron is in the $+1$ oxidation state.
Updated On: Apr 10, 2026
- +3
- 0
- +2
- +1
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The Correct Option is D
Solution and Explanation
Step 1: Complex Charge
The complex dissociates as $[Fe(H_2O)_5NO]^{2+}$ and $SO_4^{2-}$.
Step 2: Ligand Nature
In this specific complex, the nitric oxide ($NO$) ligand exists in the form of the nitrosyl ion ($NO^+$). Water is neutral ($H_2O = 0$).
Step 3: Calculation
Let oxidation state of $Fe$ be $x$: $x + 5(0) + (+1) = +2 \Rightarrow x = +1$.
Final Answer: (d)
The complex dissociates as $[Fe(H_2O)_5NO]^{2+}$ and $SO_4^{2-}$.
Step 2: Ligand Nature
In this specific complex, the nitric oxide ($NO$) ligand exists in the form of the nitrosyl ion ($NO^+$). Water is neutral ($H_2O = 0$).
Step 3: Calculation
Let oxidation state of $Fe$ be $x$: $x + 5(0) + (+1) = +2 \Rightarrow x = +1$.
Final Answer: (d)
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