Question:
The output voltage \(V_o\) of the circuit is:
The output voltage \(V_o\) of the circuit is:
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For difference amplifier: \( V_o = \left( \frac{R_f}{R_1} \right)(V_2 - V_1) \)
Updated On: May 26, 2025
- \(-20\ \text{V}\)
- \(20\ \text{V}\)
- \(-30\ \text{V}\)
- \(30\ \text{V}\)
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The Correct Option is D
Solution and Explanation
This is a **difference amplifier**:
\[
V_o = \left(\dfrac{R_f}{R_1}\right) (V_2 - V_1)
\]
Where:
- \(V_2 = 5\ \text{V}\),
- \(V_1 = 2\ \text{V}\),
- \(R_f = 100\ \text{k}\Omega,\ R_1 = 10\ \text{k}\Omega\)
\[ V_o = \left(\dfrac{100}{10}\right)(5 - 2) = 10 \times 3 = 30\ \text{V} \]
- \(V_1 = 2\ \text{V}\),
- \(R_f = 100\ \text{k}\Omega,\ R_1 = 10\ \text{k}\Omega\)
\[ V_o = \left(\dfrac{100}{10}\right)(5 - 2) = 10 \times 3 = 30\ \text{V} \]
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