Question:
Force on a current-carrying conductor placed in a magnetic field is given by:
Force on a current-carrying conductor placed in a magnetic field is given by:
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Remember: Maximum force occurs when conductor is perpendicular to the magnetic field (\(\theta = 90^\circ\)).
Updated On: May 26, 2025
- \( BIl \sin \theta \) Newtons
- \( BIl \cos \theta \) Newtons
- \( BIl \sin(\theta + 45^\circ) \) Newtons
- \( BIl \cos(\theta + 45^\circ) \) Newtons
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The Correct Option is A
Solution and Explanation
The magnetic force on a straight current-carrying conductor is given by:
\[
F = BIl \sin \theta
\]
Where:
- \(B\) = magnetic field,
- \(I\) = current,
- \(l\) = length of conductor,
- \(\theta\) = angle between conductor and field.
- \(I\) = current,
- \(l\) = length of conductor,
- \(\theta\) = angle between conductor and field.
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