The output of the statement: \texttt{System.out.println(Character.toUpperCase('b') + 2); is:}
Show Hint
- 66
- 100
- 68
- 98
The Correct Option is C
Solution and Explanation
The function \texttt{Character.toUpperCase('b')} converts the lowercase character \texttt{'b'} into its uppercase form. So: \[ \texttt{Character.toUpperCase('b')} = \texttt{'B'} \] Thus, the character obtained is \texttt{'B'}.
Step 2: Find the ASCII value of the character.
In Java, when a character is used in an arithmetic expression, it is automatically converted into its ASCII (or Unicode) integer value. The ASCII value of: \[ \texttt{'B'} = 66 \] So now the expression becomes: \[ 66 + 2 \]
Step 3: Perform the addition.
Now add 2 to 66: \[ 66 + 2 = 68 \] So the output printed by the statement will be: \[ 68 \]
Step 4: Compare with the given options.
- (A) 66: Incorrect. This is only the ASCII value of \texttt{'B'} before adding 2.
- (B) 100: Incorrect. This does not match the evaluated result.
- (C) 68: Correct. This is the final value after converting \texttt{'b'} to \texttt{'B'} and adding 2.
- (D) 98: Incorrect. This is the ASCII value of lowercase \texttt{'b'}, not the final result.
Final Answer:68.
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