Question:

Evaluate the Java expression:
\[ x = a * b % (++c) + (++a) + (--b); \] if \(a = 7\), \(b = 8\), \(c = 2\).

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In Java, pre-increment \((++a)\) and pre-decrement \((--b)\) change the value first, then use it in the expression.
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Solution and Explanation

Step 1: Write the given values.
We are given:
\[ a = 7, \quad b = 8, \quad c = 2 \] Step 2: Apply the pre-increment and pre-decrement operators.
In Java, \(++c\) means first increase \(c\) by \(1\), then use its value. So:
\[ ++c = 3 \] Similarly, \(++a = 8\) and \(--b = 7\).
Step 3: Substitute the updated values into the expression.
Now the expression becomes:
\[ x = 7 * 8 % 3 + 8 + 7 \] Step 4: Perform multiplication and modulus.
First multiply:
\[ 7 * 8 = 56 \] Now find modulus:
\[ 56 % 3 = 2 \] Step 5: Add the remaining terms.
Now,
\[ x = 2 + 8 + 7 \] \[ x = 17 \]
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