Step 1: Understanding the problem.
We are asked to find the number of three-letter words that can be formed from the letters of the word 'VIRUS' without repetition. The word 'VIRUS' contains 5 distinct letters: V, I, R, U, and S.
Step 2: Calculating the number of arrangements.
The number of ways to choose 3 letters from 5 distinct letters is given by the number of permutations of 3 letters from 5. This is calculated as:
\[
P(5, 3) = \frac{5!}{(5-3)!} = \frac{5!}{2!} = \frac{5 \times 4 \times 3}{1} = 60
\]
Step 3: Conclusion.
The correct answer is (C) 60, as there are 60 possible three-letter words that can be formed.
| $X_i$ | 5 | 6 | 8 | 10 |
| $F_i$ | 8 | 10 | 10 | 12 |
| X | 0 | 1 | 2 | 3 | 4 | 5 |
| P(X) | 0 | K | 2K | 3K | 4K | 5K |