Let the first term be a and the common difference be d, so the 20 terms are a, a+d, a+2d, ... , a+19d. With 20 terms, the four middle terms are the 9th, 10th, 11th and 12th terms: (a+8d), (a+9d), (a+10d), (a+11d). Their sum is 4a + 38d, which the question tells us equals -22. Simplifying, this base equation is 2a + 19d = -11, and it is already known from the question itself, before looking at either statement.
Statement 1 gives the sum of the first four terms, a + (a+d) + (a+2d) + (a+3d) = 4a + 6d = 74, i.e. 2a + 3d = 37. Combined with the base equation 2a + 19d = -11, subtracting gives 16d = -48, so d = -3, and substituting back gives a = 23. This is a unique solution, so statement 1 alone (using the equation already given in the question) is sufficient.
Statement 2 gives a - d = 26. Combined with the base equation, substitute a = d + 26 into 2a + 19d = -11: 2(d+26) + 19d = -11, so 21d = -63, d = -3, and a = 23. Again a unique solution, so statement 2 alone is also sufficient.
Since each statement, combined with the base fact already stated in the question, independently pins down a unique pair (a, d), and both approaches even land on the same actual values (a = 23, d = -3), either statement alone is sufficient. The answer is (d).