Question:

The number of stereoisomers for pent-3-en-2-ol is

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Maximum stereoisomers = $2^n$ for n chiral centers + geometrical isomers.
Updated On: Apr 8, 2026
  • 2
  • 4
  • 3
  • 5
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
Stereoisomers include both geometrical and optical isomers.
Step 2: Detailed Explanation:
Pent-3-en-2-ol has one chiral carbon and one double bond showing geometrical isomerism, giving total 4 stereoisomers.
Step 3: Final Answer:
There are 4 stereoisomers.
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