The number of species having a square planar shape from the following is __
\(XeF_4, SF_4, SiF_4, BF^-_4 BrF^-_4,[Cu(NH_3)_4]^{2+}, [FeCl_4]^{2-}, [PtCl_4]^{2-}\)
\(XeF_4, SF_4, SiF_4, BF^-_4 BrF^-_4,[Cu(NH_3)_4]^{2+}, [FeCl_4]^{2-}, [PtCl_4]^{2-}\)
Correct Answer: 4
Approach Solution - 1
Square Planar Molecular Geometry Analysis
To determine the shapes of these species, we need to consider their electron domain geometry and the effect of lone pairs. Square planar geometry arises from an octahedral electron domain geometry with two lone pairs occupying axial positions. It can also arise from dsp2 hybridisation when the central atom has a d8 configuration in a complex ion.
Let’s analyze each species:
- \( \text{XeF}_4 \): Xe has 8 valence electrons, and 4 are used for bonding with F. This leaves 4 electrons (2 lone pairs). \( \text{XeF}_4 \) has 6 electron domains (4 bonding, 2 lone pairs) adopting an octahedral electron domain geometry. The lone pairs occupy axial positions, resulting in a square planar molecular geometry.
- \( \text{SF}_4 \): S has 6 valence electrons, 4 used for bonding. This leaves 2 electrons (1 lone pair). \( \text{SF}_4 \) has 5 electron domains (4 bonding and 1 lone pair) with a trigonal bipyramidal electron domain geometry. The lone pair occupies an equatorial position leading to a see-saw shape.
- \( \text{SiF}_4 \): Si has 4 valence electrons, all used for bonding. \( \text{SiF}_4 \) has 4 electron domains (4 bonding, 0 lone pairs) and is tetrahedral.
- \( \text{BrF}_4^- \): Br has 7 valence electrons + 1 (from the negative charge) = 8 electrons. 4 are used for bonding. This leaves 4 electrons (2 lone pairs). \( \text{BrF}_4^- \) has 6 electron domains (4 bonding, 2 non-bonding), adopting an octahedral electron geometry. The two lone pairs are in the axial positions, leading to a square planar molecular geometry.
- \( [\text{Cu(NH}_3)_4]^{2+} \): \( \text{Cu}^{2+} \) is a d9 system. Due to Jahn Teller distortion, this complex prefers to be a distorted square planar structure rather than a perfect square planar shape. For this type of question, it’s usually counted as a square planar complex.
- \( [\text{FeCl}_4]^{2-} \): \( \text{Fe}^{2+} \) is a d6 system, which is generally tetrahedral when dealing with weak field ligands.
- \( [\text{PtCl}_4]^{2-} \): \( \text{Pt}^{2+} \) is a d8 system. These often form square planar complexes due to dsp2 hybridization.
Conclusion:
Therefore, \( \text{XeF}_4 \), \( \text{BrF}_4^- \), \( [\text{Cu(NH}_3)_4]^{2+} \), and \( [\text{PtCl}_4]^{2-} \) are square planar. The answer is 4.
Approach Solution -2
Top JEE Main Chemistry Questions
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- At equilibrium the concentrations of and in a sealed vessel at . What will be for the reaction
- Find out the major products from the following reactions
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
- The correct order of atomic radii is:
Top JEE Main Chemical Reactions of Alcohols Phenols and Ethers Questions
- What happens when methane undergoes combustion in systems A and B respectively?
- Given below are two statements, one is labelled as Assertion: A and the other is labelled as Reason R.
Assertion: A Isotopes of hydrogen have almost same chemical properties, but difference in their rates of reaction.
Reason: R Isotopes of hydrogen have different enthalpy of bond dissociation.
In the light of the above statements, choose the most appropriate answer from the options given below - better method for preparation of bef2 among the following is
- The correct group of halide ions which can be oxidised by oxygen in acidic medium is
- Which of the following complexes will exhibit maximum attraction to an applied magnetic field?
Top JEE Main Questions
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,