Which of the following complexes will exhibit maximum attraction to an applied magnetic field?
- [Co(en)3]3+
- [Co(H2O)6]2+
- [Zn(H2O)6]2+
- [Ni(H2O6]2+
The Correct Option is B
Solution and Explanation
The attraction of a complex to a magnetic field depends on the number of unpaired electrons in the complex. Let us analyze each given complex:
1.[Zn(H\(_2\)O)\(_6\)]\(^{2+}\): The electronic configuration of Zn\(^{2+}\) is \( 3d^{10} \). It has no unpaired electrons, so it is diamagnetic.
2. [Ni(H\(_2\)O)\(_6\)]\(^{2+}\): The electronic configuration of Ni\(^{2+}\) is \( 3d^8 \). In an octahedral field, this gives a \( t_{2g}^6 e_g^2 \) configuration, with 2 unpaired electrons.
3. [Co(en)\(_3\)]\(^{3+}\): The electronic configuration of Co\(^{3+}\) is \( 3d^6 \). Due to strong-field ligands (en), it undergoes pairing, resulting in a \( t_{2g}^6 e_g^0 \) configuration with no unpaired electrons. It is diamagnetic.
4. [Co(H\(_2\)O)\(_6\)]\(^{2+}\): The electronic configuration of Co\(^{2+}\) is \( 3d^7 \). In an octahedral field with weak-field ligands like water, it gives a \( t_{2g}^5 e_g^2 \) configuration with 3 unpaired electrons. Hence, [Co(H\(_2\)O)\(_6\)]\(^{2+}\) has the maximum number of unpaired electrons and will exhibit the maximum attraction to an applied magnetic field.
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