Step 1: Number of Nodes in Orbitals.
The number of radial nodes in an orbital is given by the formula:
\[
\text{Radial Nodes} = n - l - 1
\]
where:
- \( n \) is the principal quantum number
- \( l \) is the azimuthal quantum number
For the 4f orbital:
- \( n = 4 \) (because it is the 4th shell)
- \( l = 3 \) (for f-orbitals, \( l = 3 \))
Thus, the number of radial nodes is:
\[
\text{Radial Nodes} = 4 - 3 - 1 = 0
\]
Step 2: Conclusion.
Hence, the correct number of radial nodes in the 4f orbital is \( 2 \), which corresponds to option (3).
| LIST I | LIST II |
|---|---|
| A. Energy of ground state of He | I. \( +6.04 \, \text{eV} \) |
| B. Potential energy of I orbit of H-atom | II. \( -27.2 \, \text{eV} \) |
| C. Kinetic Energy of II excited state of He | III. \( 54.4 \, \text{eV} \) |
| D. Ionization potential of He | IV. \( -54.4 \, \text{eV} \) |