120
6
12
We are tasked with finding the number of four-digit numbers that satisfy the following conditions:
The first digit must ensure the number is between 5000 and 10000. Therefore, it must be \( 5 \), \( 7 \), or \( 9 \). This gives us 3 choices for the first digit.
Once the first digit is chosen, there are 4 remaining digits in the set \( \{1, 3, 5, 7, 9\} \) (excluding the chosen first digit). The second digit can then be any one of these 4 digits, giving 4 choices for the second digit. For the third digit, we are left with 3 choices (the remaining digits after the first two have been selected). Similarly, for the fourth digit, there are 2 remaining choices.
The total number of valid numbers is given by the product of choices for each position:
\[ 3 \times 4 \times 3 \times 2 = 72 \]
Thus, there are 72 four-digit numbers that satisfy the given conditions.
The correct answer is (A) : 72
Numbers between 5000&10000
Using digits 1,3,5,7,9

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,
A permutation is an arrangement of multiple objects in a particular order taken a few or all at a time. The formula for permutation is as follows:
\(^nP_r = \frac{n!}{(n-r)!}\)
nPr = permutation
n = total number of objects
r = number of objects selected