Question:

The number of moles of hydrogen molecules required to produce 20 moles of ammonia through Haber's process is

Updated On: Apr 25, 2026
  • 10
  • 20
  • 30
  • 40
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The Correct Option is C

Solution and Explanation

To solve this problem, we need to consider the chemical reaction involved in the production of ammonia through the Haber process. The balanced chemical equation for this reaction is:

N_2(g) + 3H_2(g) \rightarrow 2NH_3(g)

This equation tells us that 1 mole of nitrogen gas reacts with 3 moles of hydrogen gas to produce 2 moles of ammonia. Thus, the stoichiometric ratio between hydrogen and ammonia is 3:2.

Given in the problem, we need to produce 20 moles of ammonia. Let's calculate the number of moles of hydrogen required:

According to the stoichiometric ratio, 2 moles of ammonia require 3 moles of hydrogen. Therefore, to find out how many moles of hydrogen are needed for 20 moles of ammonia, we set up the proportion:

\frac{3 \text{ moles of } H_2}{2 \text{ moles of } NH_3} = \frac{x \text{ moles of } H_2}{20 \text{ moles of } NH_3}

Cross-multiplying gives us:

2x = 20 \times 3

2x = 60

Dividing each side by 2 to solve for x gives:

x = \frac{60}{2} = 30

Therefore, 30 moles of hydrogen gas are required to produce 20 moles of ammonia.

Hence, the correct answer is 30.

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