To solve this problem, we need to consider the chemical reaction involved in the production of ammonia through the Haber process. The balanced chemical equation for this reaction is:
N_2(g) + 3H_2(g) \rightarrow 2NH_3(g)
This equation tells us that 1 mole of nitrogen gas reacts with 3 moles of hydrogen gas to produce 2 moles of ammonia. Thus, the stoichiometric ratio between hydrogen and ammonia is 3:2.
Given in the problem, we need to produce 20 moles of ammonia. Let's calculate the number of moles of hydrogen required:
According to the stoichiometric ratio, 2 moles of ammonia require 3 moles of hydrogen. Therefore, to find out how many moles of hydrogen are needed for 20 moles of ammonia, we set up the proportion:
\frac{3 \text{ moles of } H_2}{2 \text{ moles of } NH_3} = \frac{x \text{ moles of } H_2}{20 \text{ moles of } NH_3}
Cross-multiplying gives us:
2x = 20 \times 3
2x = 60
Dividing each side by 2 to solve for x gives:
x = \frac{60}{2} = 30
Therefore, 30 moles of hydrogen gas are required to produce 20 moles of ammonia.
Hence, the correct answer is 30.