The number of lattice points in a face-centered cubic (FCC) unit cell is:
Show Hint
- 1
- 2
- 3
- 4
The Correct Option is D
Solution and Explanation
Step 1: Atoms in corners.
Each FCC unit cell has atoms at 8 corners. Contribution from each corner = $\tfrac{1}{8}$.
\[
8 \times \tfrac{1}{8} = 1 \ \text{atom from corners}
\]
Step 2: Atoms on faces.
Each of the 6 faces has one atom at its center. Contribution from each face = $\tfrac{1}{2}$.
\[
6 \times \tfrac{1}{2} = 3 \ \text{atoms from faces}
\]
Step 3: Total lattice points.
\[
1 + 3 = 4
\]
Final Answer:
\[
\boxed{4}
\]
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