The number of 
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Correct Answer: 5
Solution and Explanation
Tripeptide Asp–Glu–Lys has two peptide (amide) bonds: 2 C=O.
Aspartic acid side chain \(-\mathrm{CH_2COOH}\): 1 C=O.
Glutamic acid side chain \(-\mathrm{CH_2CH_2COOH}\): 1 C=O.
Lysine side chain \(-(\mathrm{CH_2})_4\mathrm{NH_2}\): none. The free C-terminal \(-\mathrm{COOH}\) of Lys: 1 C=O.
Total = 2 + 1 + 1 + 1 = 5.
Answer: 5
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