Question

The number of enantiomers of the compound \( \text{CH}_3 \text{CHBr} \text{CHBrCOOH} \) is

• A. 0
• B. 1
• C. 3
• D. 4

Hint:

The number of enantiomers is determined by the number of chiral centers in the molecule. For \( n \) chiral centers, the number of stereoisomers is \( 2^n \).

Answer 1

The Correct Option is D

Step 1: Analyze the compound's symmetry.
The compound contains two chiral centers (the carbon atoms attached to \( \text{Br} \)), so it can have 4 enantiomers (two pairs of non-superimposable mirror images).
Step 2: Conclusion.
The number of enantiomers of the compound is 4. Final Answer: \[ \boxed{4} \]