The number of enantiomers of the compound \( \text{CH}_3 \text{CHBr} \text{CHBrCOOH} \) is
Show Hint
The number of enantiomers is determined by the number of chiral centers in the molecule. For \( n \) chiral centers, the number of stereoisomers is \( 2^n \).
Step 1: Analyze the compound's symmetry.
The compound contains two chiral centers (the carbon atoms attached to \( \text{Br} \)), so it can have 4 enantiomers (two pairs of non-superimposable mirror images).
Step 2: Conclusion.
The number of enantiomers of the compound is 4.
Final Answer:
\[
\boxed{4}
\]