To determine the number of electrons present in all the completely filled subshells with principal quantum number n=4 and spin quantum number s=+½, we first identify the available subshells for n=4. These are 4s, 4p, 4d, and 4f.
Each subshell can hold a specific number of electrons:
Next, since we are only interested in electrons with s=+½, we consider half of those in each subshell:
| Subshell | Total Electrons | Electrons with s=+½ |
|---|---|---|
| 4s | 2 | 1 |
| 4p | 6 | 3 |
| 4d | 10 | 5 |
| 4f | 14 | 7 |
Summing these, the total number of electrons with s=+½ is 1+3+5+7=16.
This value fits the expected range of 16,16, confirming its correctness. Therefore, the number of electrons in all completely filled subshells with n=4 and s=+½ is 16.
For n = 4, the possible subshells and their electron capacities are:
So, the total number of electrons is 16.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)