Question

The number of electrons delivered at the cathode during electrolysis by a current of $1$ ampere in $60$ seconds is (change on electron = $1.60 \times 10^{-19} C)$

• A. $6 \times 10^{23}$
• B. $6 \times 10^{20}$
• C. $3.75 \times 10^{20}$
• D. $7.48 \times 10^{23}$

Answer 1

The Correct Option is C

Charge and Number of Electrons Calculation 

The relationship between charge (\( Q \)) and the number of electrons (\( n \)) is given by:

\(Q = ne\)

The total charge is also related to current and time:

\(I \times t = ne\)

To find the number of electrons, we can solve for \( n \):

\(n = \frac{I \times t}{e}\)

Substituting the given values (current = 1 A, time = 60 seconds, and the elementary charge \( e = 1.6 \times 10^{-19} \) C):

\(n = \frac{1 \times 60}{1.6 \times 10^{-19}}\)

Finally, calculating \( n \):

\(n = 3.75 \times 10^{20}\)

Conclusion:

The number of electrons is \( 3.75 \times 10^{20} \).