Step 1: Understand the number.
The number is 311311311311311311311, which is the block "311" written 7 times in a row, giving \(7\times3=21\) digits.
Step 2: Check divisibility by 3.
A number is divisible by 3 only when its digit sum is divisible by 3.
Each block "311" has digit sum \(3+1+1=5\).
With 7 blocks, the total digit sum is \(7\times5=35\).
Since 35 is not divisible by 3 (its own digit sum \(3+5=8\) is not a multiple of 3), the number is not divisible by 3.
Step 3: Check divisibility by 11.
A number is divisible by 11 only when the difference between the sum of digits at odd positions and the sum of digits at even positions (counted from the right) is a multiple of 11, including 0.
Splitting the 21 digits this way gives an odd-position sum of 19 and an even-position sum of 16.
\[ 19-16 = 3 \]
Since 3 is not a multiple of 11, the number is not divisible by 11 either.
Step 4: Final Answer.
The number fails both tests, so it is neither divisible by 3 nor by 11. This rules out option (A), option (B) and option (C).
\[ \boxed{\text{Neither divisible by 3 nor by 11}} \]